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3 years ago

Find the LCM of 5,10 and 15

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer:

first write 5 ,10,15 .
And then after divides altogether with 5.
Then after answer comes 30

Kaylis [27]3 years ago

3 0

Write a few multiples of each number
5- 10,15,20,25,30
10-20,30,40,50
15-15,30,45,60

The first common multiple is 30

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How to factor 3x^2-10x-8?

Soloha48 [4]

<em> $answer \\(x - 4)(3x + 2) \\ solution \\ {3x}^{2} - 10x - 8 \\ = {3x}^{2} - (12 - 2)x - 8 \\ = {3x}^{2} - 12x + 2x - 8 \\ = 3x(x - 4) + 2(x - 4) \\ = (x - 4)(3x + 2) \\ hope \: it \: helps$ </em>

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3 years ago

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3 years ago

Emissions of sulfur dioxide by industry sett off chemical changes in the atmosphere that result in "acid rain". The acidity of l

horsena [70]

Answer:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P value

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

Step-by-step explanation:

Data given and notation

$\bar X=4.8$ represent the sample mean

$\sigma=0.5$ represent the population standard deviation

$n$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:

Null hypothesis: $\mu \geq 5$

Alternative hypothesis: $\mu < 5$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P-value

Since is a left tailed test the p value would be:

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

5 0

3 years ago

Which of the following functions is graphed below?

sasho [114]

Answer:

2nd choice B.

Step-by-step explanation:

You can use the options A-D to help you eliminate pretty quickly without actually graphing

So first chose says you have the graph on the left when x<1 But you should see our visual actually says we want to include what happens at 1 (the filled dot) so this isn't the answer

Second choice Possible

Third choice... I'm just going to look at one of the parts... x^2+4 for x<=1 says we should have part of a parabola to the left of x=1 (inclusive) but there is not parabola in our visual

Fourth choice: same reason as third choice

Answer is the 2nd

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2 years ago

A jet moving at constant speed traveled 6,600 km in 3 hours. What was the speed of the jet?

DanielleElmas [232]

Answer:

The speed of the jet is $2,200\frac{km}{h}$

Step-by-step explanation:

The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.

1. Write the general equation for the speed:

$Speed=\frac{Distance}{Time}$

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:

$Speed=\frac{6,600km}{3hours}$

$Speed=2,200\frac{km}{h}$

Therefore the speed of the jet is $2,200\frac{km}{h}$

3 0

3 years ago

Read 2 more answers

Find the LCM of 5,10 and 15​

Find the LCM of 5,10 and 15