<span>x^0 y^-3 / x^2 y^-1
= 1 / </span> x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2<span>
= 1/(x^2 y^2)</span>
13. 44 + 40 = 84
14. 15 + 81 = 96
15. 13 + 52 = 65
16. 64 + 28 = 92
Answer:
b
Step-by-step explanation:
=a^1/x=x√a
(a^1/x) ^b= x√a^b
Point slope form of a line:

where

is your slope and

is a point on your line.
For a line with a slope of 3/5 that passes through (10, -2)...

Let's plug these values into our formula.

Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.

There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.