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Reika [66]
2 years ago
15

A cylinder has a diameter of 10 inches in the height four times the radius what is the volume

Mathematics
1 answer:
SVEN [57.7K]2 years ago
8 0

Answer:

500π in^3

Step-by-step explanation:

The radius is half the diameter, so the radius is 5 in. Since the height is four times that, the height is 20 in.

The equation for the volume of a cylinder is:

V = \pi r^{2}h

We can plug in the radius and height:

V = \pi  \times (5)^{2} \times 20\\V = \pi \times 25 \times 20\\V = 500\pi in^{3}

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Evaluate the expression when x = 6
ivolga24 [154]

Answer:

76

4+2×6×6(x=6)

4+72

76

4 0
2 years ago
Not sure how to solve this one
Alex73 [517]

Answer:

x\approx 63.4^0

Step-by-step explanation:

In the given right triangle,

Measure of angle = x°

Opposite side of the angle = 12 units

Adjacent side of the angle = 6 units

By taking tangent ratio of the given angle,

tan(x°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

           = \frac{12}{6}

           = 2

x^0=\text{tan}^{-1}(2)}

x=63.43^0

x\approx 63.4^0

4 0
2 years ago
HELP PLEASE!!!!!!!!?!??
lianna [129]

Answer:

A

B

C

Step-by-step explanation:

I think this is correct

6 0
2 years ago
Read 2 more answers
Solve for x in the triangle. Round your answer to the nearest tenth.
hodyreva [135]

Answer:

x ≈ 11.7

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = \frac{adjacent}{hypotenuse} = \frac{x}{13} ( multiply both sides by 13 )

13 × cos26° = x , then

x ≈ 11.7 ( to the nearest tenth )

4 0
2 years ago
Consider the following series. 1 9 1 18 1 27 1 36 1 45 Determine whether the series is convergent or divergent. Justify your ans
Vedmedyk [2.9K]

Answer:

<em>Diverges; the limit of the terms, an, is not 0 as n goes to infinity</em>

Step-by-step explanation:

<u>Convergence of Infinite Series</u>

The series is given as the terms

1 , 9 , 1 , 18 , 27 , 1 , 36 , 1 , 45 ...

For a series to be convergent, the limit of the general term an when n goes to infinity must be 0. In such cases, the sum of all terms tends to a fixed value.

Our series has two clearly different sequences, which define it as a piecewise general term:

If n is odd, then

a_n=1

Otherwise, an is an arithmetic series starting from 9 with a common difference of 9, that is

a_n=9+9(n/2-1)=4.5n

if n is even.

If we take the limit as n goes to infinity, we don't know which one should be selected, thus we must assume that any of them is a correct option, therefore both of them should converge.

The limit of the function

a_n=1

is 1 when n goes to infinity. Since it's not 0, this piece is not convergent and the entire series isn't either.

But it goes worse because of the limit of the second piece

a_n=4.5n

when n goes to infinity is infinite.

The answer is

<em>Diverges; the limit of the terms, an, is not 0 as n goes to infinity</em>

8 0
3 years ago
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