Answer:
Graph A
Step-by-step explanation:
Its mean graph should intersect x axis at x = 7 and x = - 1. This everything is satisfied by graph A.
For the month of November in a certain city, 88% of the days are cloudy. Also in the month of November in the same city, 54%
1 answer:
Answer:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Step-by-step explanation:
We have these following probabilities:
An 88% probability that the day is cloudy.
An 54% probability that the day is both foggy and cloudy.
What is the probability that a randomly selected day in November will be foggy if it is cloudy?
This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
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Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression
The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values