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pochemuha
3 years ago
6

What is the excluded value of x / x^2 +2x -3​

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

x = - 3 and x = 1

Step-by-step explanation:

Given the rational expression

\frac{x}{x^2+2x-3}

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is

x² + 2x - 3 = 0 ← in standard form

(x + 3)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 1 = 0 ⇒ x = 1

Thus x = 1 and x = - 3 are both excluded values

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Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

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Part 3) 98% Confidence Interval
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Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
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Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
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