Question

19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

Answer 1

Answer:

29.4 meters

Step-by-step explanation:

Given the following :

A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

distance it moved between two positions. Use the "distance on the number line "formula

Initial Position or distance of submarine before ascension = 56.8 meters

Final position after ascension = 27.4 meters

The distance moved by the submarine between the two positions can be obtained by.

(Initial distance - Final distance)

(56.8 - 27.4) = 29.4 meters