For this case we have to:
x: Let the variable representing the unknown number
We algebraically rewrite the given expression:
Eleven more than four times a number, is represented as:
The number less 7, is represented as:
Thus, the complete expression is:
We subtract x from both sides of the equation:
We subtract 11 from both sides of the equation:
Equal signs are added and the same sign is placed:
We divide by 3 on both sides of the equation:
Answer:
Answer:
272,100
This is because 62 rounds up
Answer:
a) bb, bg, gb, gg
b) 25% probability of getting two green dash eyed children.
c) 50% probability of getting exactly one blue dash eyed child and one green dash eyed child.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
Total of eight outcomes.
a. Construct a similar sample space for the possible eye color outcomes (using b for blue dash eyed and g for green dash eyed) of two children.
bb, bg, gb, gg
b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two green dash eyed children.
Four outcomes.
Of those, in one(gg), you get two green dash eyed children.
1/4 = 0.25
25% probability of getting two green dash eyed children.
c. Find the probability of getting exactly one blue dash eyed child and one green dash eyed child.
In two of those(bg and gb) you get one blue dash eyed child and one green dash eyed child.
2/4 = 0.5
50% probability of getting exactly one blue dash eyed child and one green dash eyed child.
I will answer second attachment and after since I can't see the firs attachment
2nd attachment
if x is negative, then the first number gets infinitely small
look at the second number, the first 2 is -2 which is wrong since it should be +2
3rd option is not because if x=-2, then y=1
answer is D
3rd attachment
2nd: f(x)=60*1.15^x
3rd: no xint
6th: after 7.86 years value tripples
7th maybe: after 8 years value is 183.51, not exatly 184.00
4th attachment
nth score is
f(n)=57+4(n-1)
9th is
f(9)=57+4(9-1)
57+32=89
answer is C 89
5th
f(t)=23000(1.02)^t
t=time in years from 23000
