Answer:
<em>6, 10 and 8</em>
Step-by-step explanation:
Given the recursive function an = an-1-(an-2 - 4), when a5 =-2 and a6 = 0?
a6 = a5 - (a4 - 4)
0 = -2 - (14 - 4)
2 = - (a4 - 4)
-2 = a4 - 4
a4 = -2 + 4
a4 = 2
a5 = a4 - (a3 - 4)
-2 = 2 - (a3 - 4)
-2-2 = - (a3 - 4)
-4 = -(a3 - 4)
4 = a3 - 4
a3 = 4+4
a3 = 8
Also
a4 = a3 - (a2 - 4)
2 = 8 - (a2 - 4)
2-8 = - (a2 - 4)
-6 = -(a2 - 4)
6 = a2 - 4
a2 = 6+4
a2 = 10
a3 = a2 - (a1 - 4)
8 = 10 - (a1 - 4)
8-10 = - (a1 - 4)
-2 = -(a1 - 4)
2 = a1 - 4
a1 = 2+4
a1 = 6
<em>Hence the first 3 terms are 6, 10 and 8</em>
Answer:
B in the photo
Step-by-step explanation:
another way to write the problem:
square root is also taking the 1/2 power:

since they are raised to the same power:

Answer:
115
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 7 - 1 = 13 - 7 = 19 - 13 = 25 - 19 = 6
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 6 , thus
a₂₀ = 1 + (19 × 6) = 1 + 114 = 115
Answer:
In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.
Step-by-step explanation:
In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.