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3 years ago

I need help with a practice problem! ASAP!

Mathematics

2 answers:

Anna [14]3 years ago

6 0

Answer:

c + a = 530

3c + 4a = 1740

Step-by-step explanation:

Ok, let's analyze what the question is telling us. From what I see, there are two important statements - "sold a total of 530 tickets" and "the total amount collected was $1740". Now let's think about how we can represent these using the variables given to us.

Well, we know the number of tickets can just be represented by totalling the number of children tickets and adult tickets sold. So we can write:

c + a = 530

We also know how much each ticket is worth (child - $3, adult -$4), and we can calculate the total amount of money made by multiplying the amount of money each ticket is worth by the number of tickets sold. So we can say the total amount for the children's tickets is 3c and the total amount of adult tickets is 4a. So the total can be represented by:

3c + 4a = 1740

Stells [14]3 years ago

4 0

Answer: See bolded equations

Step-by-step explanation:

The system of equations can be used to solve this problem. C is child ticket and a is adult ticket.

Equation 1

3c+4a=1740

This equation comes from the cost of the tickets. 3c is the cost of $3 per child ticket and 4a is the cost of $4 per adult ticket. 1740 is the total amount collected.

Equation 2

c+a=530

This comes from the number of tickets sold. The c+a is the total of child and adult tickets sold and 530 is the total amount of tickets.

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FromTheMoon [43]

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3 years ago

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3 years ago

Southwest Co-op produces bags of fertilizer, and it is concerned about impurity content. It is believed that the weights of impu

Harman [31]

Answer:

a) 0.216

b) 0.1587

c) 0.369

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 12.2 grams

Standard Deviation, σ = 2.8 grams

We are given that the distribution of weights of impurities per bag is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

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P(x < 10)

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b) P(contains more than 15 grams of impurities)

P(x > 15)

$P( x > 15) = P( z > \displaystyle\frac{15 - 12.2}{2.8}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 610) = 1 - 0.8413 = 0.1587 = 15.87\%$

c) P(contains between 12 and 15 grams of impurities)

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$P(12 \leq x \leq 15) = 36.9%$

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4 years ago

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4 years ago

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VashaNatasha [74]

I hope this helps you

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3 years ago