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patriot [66]
3 years ago
8

Cos(x+y)/cos(x)sin(y)=cot(y)-tan(x)

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0
So there is an identity we'll need to use to solve this:

cos(x+y) = cosxcosy - sinxsiny

replace the numerator with the right hand side of that identity and we get:

(cosxcosy - sinxsiny)/cosxsiny

Separate the numerator into 2 fractions and we get:

cosxcosycosxsiny- sinxsiny/cosxsiny

the cosx's cancel on the left fraction, the siny's cancel on the right fraction and we're left with:

cosy/siny - sinx/cosx

which simplifies to:

coty - tanx




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We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.

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