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faltersainse [42]
3 years ago
5

Solve for x: 36 - 6x = 4x - 64

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

x=10

Step-by-step explanation:

insens350 [35]3 years ago
5 0

Answer:

x = 10

Step-by-step explanation:

36 - 6x = 4x - 64

36 + 64 = 4x + 6x

100 = 10x

x = 10

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Sherri spent 4 hours exercising last week. If 5/6 of the time was spent jogging, how much time did she spend jogging?
Mila [183]
THat would be 5/6 * 4 = 20/6 = 3 1/3 hours jogging.
7 0
3 years ago
Which of the following represents a function?
Iteru [2.4K]

Functions cannot have different values of y for the same value of x. Now let us check each case one at a time.

<u>First Case:</u> For the same value of x=-1, y has two different values of 7 and 1, which is not allowed in a function. Therefore, the first case is not a function.

<u>Second Case:</u> For the same value of x=-1, y has two different values of -5 and 1, which is not allowed in a function. Therefore, the second case is not a function.

<u>Third Case:</u> For the same value of x=3, y has two different values of 2 and 4, which is not allowed in a function. Therefore, third case is not a function.

<u>Fourth Case:</u> In this case no value of x is same. So, this is a function.

4 0
4 years ago
Read 2 more answers
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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Eduardwww [97]
4 cans.
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3 years ago
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Thats not evan an answer choise
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What are you talking about?

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3 years ago
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