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Norma-Jean [14]
3 years ago
9

PLEASE HELP GIVING 30 POINTS!!!! 1 6 ≥ 6 + x/2

Mathematics
2 answers:
DENIUS [597]3 years ago
4 0

Answer:

x ≤ 20

Step-by-step explanation:

Subtract 66 from both sides.

16 − 6 ≥ x/2.

Simplify  16 − 6 = 10.

10 ≥ x/2.

Multiply both sides by 22.

10 × 2 ≥ x.

Simplifiy 10 x 2 = 20.

20 ≥ x.

Switch sides.  

x ≤ 20.

Temka [501]3 years ago
3 0

The answer is x<20. Hope that helps.

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Please choose the answer that describes the scientific notation for 5,098,000.
avanturin [10]
Scientific notation is the representation of a number in a power of ten, with a sequence of digits placing the comma after the first digit, and the power or then that is mathematically consistent with the number. For example 400 is 4.00 * 10^2; 3100 is 3.100 * 10^4; 13421 = 1.3421 * 10 ^4. It is important that you have only one digit before the comma. So, 5,098,00 is 5.098 * 1,000,00 = 5.098 * 10^6. <span>The answer is the option c. 5.098 * 10^6.</span>
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3 years ago
Simplify (2x^2y)^3 (-3xy^2)^2
solniwko [45]
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The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th
ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

\frac{99.7\%}{2}=49.85\%

Therefore, approximately 49.85\% of lightbulb replacement requests numbering between 38 and 56.

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3 years ago
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