Let 
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so
where 
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is
where 
denotes the CDF of , and 
denotes the inverse CDF. We have
Similarly, because 20% of students obtain less than 40 marks, we have
so that
Then 
are such that
and we find
to ketha ay ayu uhh uh la toca bella
Use the formula 1/2(base1+base2)height. Substitute the values.
Answer:
C (-6,10) - A)x^7-0.1/4
Step-by-step explanation:
Hope this helps
Answer:
<h2>
y = 6x - 1</h2>
Step-by-step explanation:
(0, -1) ⇒ x₁ = 0, y₁ = -1
(1, 5) ⇒ x₂ = 1, y₂ = 5
So the slope:
The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.
(0, -1) ⇒ x₀ = 0, y₀ = -1 ⇒ b = -1
Therefore:
y = 6x - 1 ← the slope-intercept form of the equation
