(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
Well I don't know. Let's see . . .
The square of 1.3 is 1.69 .
The square of 1.4 is 1.96 .
' 2 ' is not between 1.69 and 1.96 , so the square root of 2
is not between 1.3 and 1.4 .
(The square root of 2 is 1.414.... . That's a little bit past 1.4 .)
Answer:
12.56cm.
Step-by-step explanation:
Given that the diameter of a circle is 4 centimeters
The equation to find the circumference would be C=πd
C=3.14x4
=12.56
The circumference of the circle would be 12.56cm.
Hope this helps :)
: -
:
7^2-7-8^2+1
| Evaluate the
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\/
49-7-8^2+1 = 49-7-64+1
--+
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\/
(-)
Here is your answer:
There are two ways you can solve this equation:
1. You could round each decimal then divide:
16.8 --> 17 & 4.96 --> 5
"17 ÷ 5 = 3.4"
2. You could just divide:
"16.8 ÷ 4.96 = 3.38"
(Remember depending on the way you have to solve it would determine your answer.)
Hope this helps!
