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3 years ago

CAN SOMEONE HELP MEEE

Mathematics

1 answer:

timurjin [86]3 years ago

8 0

Then answer that makes that most sense would have to be the one that says
"No values of X make the equation true"
I hope that helped!!!!

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Anybody help me to solve this question.

Mumz [18]

Answer:

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP$

Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

To prove: $\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}$ are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

$2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab$

Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

Which is the result of AP

Hence proved

6 0

3 years ago

Please help ❤️ What percent of 24 is 15?

Kipish [7]

Answer:

62.5

Step-by-step explanation:

There ya gooo :)

5 0

3 years ago

Read 2 more answers

Janet deducted $5 on Monday and another $6 on Tuesday from her savings account. How much money did Janet deduct?

emmasim [6.3K]

A total of 5+6 for the total deduction so 11$. Her savings account has a total of -11$ since Monday as another way of phrasing it

7 0

3 years ago

If two circles have the same circumfrence, what do you know about their areas

blagie [28]

Answer:

They would have the same area.

Step-by-step explanation:

The area of a circle = pi x the circumfrence. or pi x the radious squared. so if they had the same circumfrence they would have the same area.

3 0

4 years ago

Apply the distributive property to factor out the greatest common factor. 16+36=16+36=

ololo11 [35]

To eliminate the biggest common factor, use the distributive property: Solution: 16 + 36 = 4 (4 + 9)

To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

Due to that,

To remove the most significant common factor, we must use the distributive property.

Given expression:16 + 36

1, 2, 4, 8, and 16 make up the number 16.

1, 2, 3, 4, 6, 9, 12, 18, and 36 make up the number 36.

Then, 4 is the most prevalent component.

distributed property

The formula is ab + bc

subtracting 4 from the supplied expression.

Therefore, the distributive property is used.

Learn more about distributive property here :

https://brainly.in/question/7963814

#SPJ4

6 0

2 years ago