9514 1404 393
Answer:
5x +y = 16
Step-by-step explanation:
Given a point and slope, it often works well to start with the point-slope form of the equation for a line:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Your point and slope make this ...
y -6 = -5(x -2)
y -6 = -5x +10 . . . . . . eliminate parentheses
5x +y = 16 . . . . . . . . . add 5x+6 to both sides; your standard form equation
Answer:
1.) Y = 5/3 X + 4
2.) Y = 9/4 X - 27/4
Step-by-step explanation:
Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is
Y = MX + C
Where the
Slope M = 5/3
Coordinate = (-3,-1) in which
X = -3, Y = -1
Substitute X, Y and M into the general linear equation to achieve C
-1 = 5/3(-3) + C
-1 = - 5 + C
C = 5 - 1
C = 4
Substitute C and M back into the general linear equation.
Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be
Y = 5/3 X + 4
2.) Also,
Slope M = 9/4
Coordinate = (3,0) where X = 3, Y = 0
Substitute X, Y and M into the general linear equation to obtain C
0 = 9/4 (3) + C
C = - 27/4
Substitutes C and M back into the general linear equation
Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)
Y = 9/4 X - 27/4
The speed of the current is 7 miles per
hour.
Step-by-step explanation:
Let × represent speed of the current.
We have been given that a motorboat
maintained a constant speed of 11 miles per
hour relative to the water in going 18 miles
upstream and then returning.
The speed of motorboat while going
upstream would be 11
The speed of motorboat while going
downstream would be 11 + 2
Time
Distance
Speed
The general form of a parabola when using the focus and directrix is:
(x - h)² = 4p(y - k) where (h, k) is the vertex of the parabola and 'p' is distance between vertex and the focus. We use this form due to the fact we can see the parabola will open up based on the directrix being below the focus. Remember that the parabola will hug the focus and run away from the directrix. The formula would be slightly different if the parabola was opening either left or right.
Given a focus of (-2,4) and a directrix of y = 0, we can assume the vertex of the parabola is exactly half way in between the focus and the directrix. The focus and vertex with be stacked one above the other, therefore the vertex will be (-2, 2) and the value of 'p' will be 2. We can now write the equation of the parabola:
(x + 2)² = 4(2)(y - 2)
(x + 2)² = 8(y - 2) Now you can solve this equation for y if you prefer solving for 'y' in terms of 'x'