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bija089 [108]
3 years ago
14

The sum of 5 consecutive integers is 65. what are those integers?

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

The numbers are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11

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-4x - 2y = -2
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Answer: -5x= -11

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Solve the quadratic function by completing the square. What are the missing pieces in the steps?
Sergeu [11.5K]

Answer:

x = -2; or x = -8

Step-by-step explanation:

Solve the quadratic function by completing the square. What are the missing pieces in the steps? -32=2(x^2+10)

-32+___=2(x2+10x+25)

18=2(x+5)^2

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Solution:

From the first line:

-32+___=2(x2+10x+25)

Also, in the second line:

18=2(x+5)^2

Let the missing piece on line 2 be a, hence:

x² + 10x + 25 = (x + 5)² and -32 + a = 18

a = 18 + 32 = 50

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18 = 2(x+5)²

Dividing through by 2:

18 / 2= [2(x+5)² / 2]

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Taking square root of both sides:

√9 = √(x + 5)²

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9 0
3 years ago
1/3(y - 2) -5/6 (y + 1) =3/4 (y - 3) - 2
Nataly [62]

Answer:

y=\frac{11}{5}

Step-by-step explanation:

Given expression

\frac{1}{3}(y-2)-\frac{5}{6}(y+1)=\frac{3}{4}(y-3)-2

To solve for y for the given expression.

Solution:

We multiply each term with the least common multiple of the denominators of the fraction in order to remove fractions.

The multiples of the denominators are:

3 = 3,6,9,<u>12</u>,15

6 = 6,<u>12</u>

4 = 4,8,<u>12</u>

The least common multiple = 12.

Multiplying each term with 12.

12.\frac{1}{3}(y-2)-12.\frac{5}{6}(y+1)=12.\frac{3}{4}(y-3)-2(12)

4(y-2)-10(y+1)=9(y-3)-24

Using distribution.

4y-8-10y-10=9y-27-24

Simplifying.

-6y-18=9y-51

Adding 6y both sides.

-6y+6y-18=9y+6y-51

-18=15y-51

Adding 51 both sides.

-18+51=15y-51+51

33=15y

Dividing both sides by 15.

\frac{33}{15}=\frac{15y}{15}

\frac{33}{15}=y

Simplifying fractions.

\frac{11}{5}=y

∴ y=\frac{11}{5}  (Answer)

7 0
3 years ago
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