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DedPeter [7]
3 years ago
14

25 POINTS!!!!!!

Mathematics
2 answers:
Gelneren [198K]3 years ago
4 0
100 like Shawn
320 like drake

ipn [44]3 years ago
3 0
330/11=30
300 like Drake
30 like Shawn Mendez
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What is the function
Ede4ka [16]
The graph shows us that the slope of f(x) is -2. Now we gotta find the slope of g(x) to compare it to that of f(x). The equation of g(x) is in slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept), so the slope is given to us for that one as well: it's -6. A line with a slope of -6 will be steeper than a line with a slope of -3, therefore the answer is B - the slope of f(x) is less than the slope of g(x).
Hope this helps.
3 0
3 years ago
A rectangle has its base on the x axis and its upper two vertices on the parabola y = 9 − x2. (a) Draw a graph of this problem.
gtnhenbr [62]

Answer:

  • (a) see attached
  • (b) width: 2x; height: y = 9-x²
  • (c) A=2x(9-x²) . . . 0 ≤ x ≤ 3
  • (d) dA/dx = -6x² +18; x=±√3
  • (e) 12√3 units²

Step-by-step explanation:

(a) The attachment shows the graph of the parabola in blue. It also shows an inscribed rectangle in black.

(b) The upper right point of the rectangle is shown in the attachment as (x, y). The dimension y is the height of the rectangle. The x-dimension is half the width of the rectangle, which is symmetrical about the y-axis. Hence the width is 2x.

(c) As with any rectangle, the area is the product of length and width:

... A = (2x)(9 -x²) . . . . . the attachment shows a graph of this

... A = -2x³ +18x . . . . . expanded form suitable for differentiation

A suitable domain for A is where both x and A are non-negative: 0 ≤ x ≤ 3.

(d) The derivative of A with respect to x is ...

... A' = -6x² +18

This is defined everywhere, so the critical values will be where A' = 0.

... 0 = -6x² +18

... 3 = x² . . . . . . . divide by -6, add 3

... √3 = x . . . . . . . -√3 is also a solution, but is not in the domain of A

(e) The rectangle will have its largest area where x=√3. That area is ...

... A = 2x(9 -x²) = 2√3(9 -(√3)²) = 2√3(6)

... A = 12√3 . . . . square units . . . . ≈ 20.785 units²

7 0
3 years ago
Mr. Khan went for a trip in his car, which travels 14.5km/h on 1 liter petrol. The
Helga [31]

Answer:

25L

Step-by-step explanation:

19396.5 km - 19034.0 km = 362.5‬ km travled

362.5 km / 14.5 km/L = 25L

5 0
3 years ago
a car uses 57 liters of gasoline for every 644 kilometers traveled. it takes 8 hours to use all the gasoline in the tank. what i
devlian [24]

Answer:

80.5 kilometers/h

Step-by-step explanation:

S=80.5km/h

D644

T8 hours

8 0
3 years ago
45.Erica Glaser deposits a check for $20,005.00 and $1.234.00 in cash. What is het total
Gwar [14]
Her total is $21,239
5 0
3 years ago
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