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yKpoI14uk [10]
4 years ago
7

A raffle has a grand prize of a Alaskan cruise valued at $7500 with a second prize of a Rocky Point vacation valued at $1100. If

each ticket costs $3 and 12000 tickets are sold, what are the expected winnings far a ticket buyer? Express to at least three decimal place accuracy in dollar form (as opposed to cents).
Mathematics
1 answer:
iris [78.8K]4 years ago
7 0

Answer:

-$2.28

Step-by-step explanation:

Given,

Total tickets = 12000,

The number of tickets in which price get = 2 ( one is $7500 and other is $ 1100 ),

Remaining tickets = 12000 - 2 = 11998,

Since, the price of each ticket = $ 3,

Thus, the value of ticket in which $ 7500 get = 7500 - 3 = $ 7497,

While, the value of ticket in which $ 1100 get = 1100 - 3 = $ 1097,

And, the value of remaining tickets = -$ 3,

( Negative sign shows the loss )

Now,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Hence, the expected winnings far a ticket buyer,

= Probability of the trial × value of the trial

=\frac{1}{12000}\times 7497 + \frac{1}{12000}\times 1097-\frac{11998}{12000}\times 3

= -2.2833333

≈ -$2.28

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