Answer:
i think d,try it and let me know pls
<em>Answer</em><em> </em><em>with</em><em> </em><em>explanation</em><em>:</em>
The Given Inequality is
|x-4|<9
Modulus of a number yields always a positive value.
→|x-4|= x-4, when, x-4≥0
That is , x≥4.
= -(x-4), when, x-4<0
means, x<4.
it can be Written as
→ -9<x-4<9
→ -9+4 < x -4+4 < 9+4
→ -5<x<13
→x∈(-5,13)
♡ <em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>♡</em>
Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).
y
r = 3 sin g becomes sqrt(x^2+y^2) = 3*-----------------------
sqrt(x^2+y^2)
Squaring both sides,
9y^2
x^2+y^2 = -----------------
x^2 + y^2
If this is correct (and I'm not convinced that it is), then (x^2+y^2)^2 = 9y^2
shows the relationship between x and y. Can anyone improve on this result?
Sixteen point nine hundred eighty five
