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The maximum height reached is 2.87 meters
<h3>What is maximum height?</h3>The maximum height of an object is the highest vertical position along the trajectory of the object.
The given parameters are:
--- the initial velocity
--- the final velocity
--- the acceleration
To calculate the height (s) of the ball, we make use of the following equation of motion:
Substitute known values
Collect like terms
Substitute 9.8 for g
Divide both sides by 19.6
Hence, the maximum height reached is 2.87 meters
Read more about acceleration and maximum height at:
The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).