I think it is the 3rd one but I might be wrong...
Answer:
Point P = (-9,11)
Step-by-step explanation:
Point M: (1,3) X and Y have the 2 on the bottom right of them
Midpoint N: (-5,7)
Point P: (X*2, Y*2)
( 1 + X*2 3 + Y*2 )
( _______ ________ ) = (-5 , 7)
( 2 , 2 )
( 1 + X*2 )
( _____ ) = -5
( 2 )
Then multiply the left equation above by 2, and that cancels out the 2 being
divided on the bottom. Also, multiply the -5 by 2 and you get -10
1 + X*2 = -10
+1 +1
__________
X*2 = -9
X = -9
( 3 + Y*2 )
( ______ ) = 7
( 2 )
Then multiply the left equation above by 2, and that cancels out the 2 being divided on the bottom. Also, multiply the 7 by 2 and you get 14
3 + Y*2 = 14
-3 -3
_________
Y*2 = 11
Y = 11
Hope this helps, good luck! :)
Answer:
Third option. 
Step-by-step explanation:
For this exercise you need to remember one of the properties for exponents.
There is a property called the "Negative property of exponents" which states the following:
Where 
As you can observe,
is the reciprocal of 
In this case you have the following expression given in the exercise:

Observe the expression. As you can notice, the base "n" has a negative exponent, which is -6.
Therefore, applying the Negative property of exponents explained at the beginning of this explanation, you can simplify the expression.
Then, the simplified form of
is the one shown below:

Answer:
The Answer is A. :)
Step-by-step explanation:
Answer:
The coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
Step-by-step explanation:
<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>
We are given a trapezoid such that the vertices of trapezoid are:
E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)
Then the new coordinates after the given transformation is:
E(-4,8) → E'(-8,-4)
F(-7,5) → F'(-5,-7)
G(-4,3) → G'(-3,-4)
H(-2,5) → H'(-5,-2)
Hence the coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).