HELP ME PLEASE

Mathematics

2 answers:

Ghella [55]3 years ago

7 0

Answer:

Step-by-step explanation:

The answer is A .

storchak [24]3 years ago

4 0

A constant function is a horizontal line.

You might be interested in

Anyone please lol ?

BartSMP [9]

Answer:

The circumference and diameter of a circle

Step-by-step explanation:

Proportional relationships can be written as $y=kx$ , where $k$ is some constant of proportionality. The formula for a circumference of a circle can be written as $C=d\pi$ , where $d$ is the diameter of the circle. Therefore, the constant of proportionality is $\pi$ and the circumference and diameter of a circle are in a proportional relationship.

8 0

3 years ago

I will give brainliest to best answer

lorasvet [3.4K]

That's a Congruent Triangle question.

The first thing that we should to analize is it: What figure is EFGH? The question say for us that $\overline{EF} \cong \overline{GH}$ and $\overline{EH} \cong \overline{GF}$ , therefore, EFGH is a parallelogram because its parallel sides are congruents (equals).

Now, we should to proof that $\triangle EFH \cong \triangle GHF$ . The simbol "≅" means congruence, that is, $\triangle EFH \cong \triangle GHF$ means that the triangles EFH and GHF are equals.

Let's proof:

$\overline{HF}$ is a diagonal of the parallelogram EFGH. When we have a diagonal in a parallelogram, the opposite angles are congruents (look at the picture: the blue angles are congruent and the red angles are congruents too). Therefore, $E\hat{F}H \cong F\hat{H}G$ and $E\hat{H}F \cong H\hat{F}G$ .

Both triangle has a comum side: the diagonal $\overline{HF}$ . The diagonal $\overline{HF}$ is between two angles that we know that are congruents, Therefore, by the case ASA (Angle, Side, Angle), we proof that $\triangle EFH \cong \triangle GHF$ .