All categories

3 years ago

Broccoli costs $ 1.50 per pound at a grocery store. How much money does 64 ounces of broccoli cost, before tax?

2 answers:

4 0

6 dollars!
Divide 64/16 because 16 ounces is a pound ,and you get 4. Afterwards multiply 4 times 1.50 and you get 6
You final answer

Ber [7]3 years ago

3 0

Note that 1lb=16oz and set up multiplication/division to cancel out units that you do not need for the final answer. (Units cancel just like numbers, this is fundamental to dimensional analysis)

64oz($1.50/16oz)=$6.00

You might be interested in

How do you know when to use the less than symbol and when to use the less than or equal to symbol when writing an inequality for

xenn [34]

Answer:

This depends on the situation. For context, you use less than when your inequality CANNOT exceed more than.

You would use less than or equal to if your inequality can be equal to a number. Here's an example.

John needs to buy X oranges and Y apples. He can AT MOST buy 10 total fruits.

x + y (equal to or less than) 45

John needs to buy X oranges and Y apples. He CANNOT buy more than 10 total fruits.

x + y < 45

5 0

3 years ago

Eric drove 804 miles in 12 hours. At the same rate, how many miles would he drive in 8 hours?

dezoksy [38]

537 miles..........................

6 0

3 years ago

Read 2 more answers

What is the value of the 6 in 861

NISA [10]

Answer:

tens-or 60

Step-by-step explanation:

the 1 is in the ones place the 6 is in the tens place and the 8 is in the hudreths place.

6 0

3 years ago

Read 2 more answers

If a yard is 3 feet long, how many inches are in a yard?

Anna [14]

36 inches is in a yard !

7 0

3 years ago

Yea I can do tomorrow it would take me to get the money back to you

Tems11 [23]

Given, the equation that represents the height of an object:

$y(t)=100t-16t^2$

First, we will find the velocity of the object which is the first derivative of the height using the method of the limits

$\frac{dy}{dt}=\lim_{h\to a}\frac{y(3+h)-y(3)}{(3+h)-(3)}$

We will find the value of the function y(t) when t = 3, and when t = 3+h

$\begin{gathered} y(3+h)=100(3+h)-16(3+h)^2 \\ y(3+h)=300+300h-16(9+6h+h^2) \\ y(3+h)=300+300h-144-96h-16h^2 \\ y(3+h)=156+4h-16h^2 \\ y(3)=100(3)-16(3)^2=156 \end{gathered}$

Substitute y(3+h) and y(3) into the expression of the limit

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}\frac{156+4h-16h^2-156}{3+h-3}=\lim_{h\to a}\frac{4h-16h^2}{h} \\ \\ \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \end{gathered}$

Where a = 0

d) compute the instantaneous velocity at t = 3

$\frac{dy}{dt}|_{t=3}=100-16*2*3=4$

So, the answer will be:

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \\ a=0 \\ \\ \frac{dy}{dt}|_{t=3}=4\text{ ft/sec} \end{gathered}$

5 0

1 year ago