Only 3 kids could eat equally because 3 is the highest number that goes into 12 and 9
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
The answer is D. 63. You have to set up a proportion as shwon in the image.
Answer:
explain what to do
Step-by-step explanation:
Assuming that all the grapes have the same probability of being randomly picked:
<h3>
How to find the probabilities?</h3>
We know that there are 8 green grapes and 15 red grapes on the bowl, so there is a total of 23 grapes.
a) Here we need to find the probability that both grapes are green. Remember that the probability of getting a green grape is equal to the quotient between the number of green grapes and the total number of grapes, this is:
P = 8/23
But then he must take another, because he already took one, the number of green grapes is 7, and the total number of grapes is 22, so for the second grape the probability is:
P' = 7/22.
The joint probability is the product of the two individual probabilities:
prob = (8/23)*(7/22) = 0.11
b) For the first green grape we know that the probability is:
P = 8/23
Then he must get a red grape. There are 15 red grapes and 22 grapes in total, so the probability is:
P' = 15/22
Then the joint probability is:
prob = (8/23)*(15/22) = 0.24
If you want to learn more about probability:
brainly.com/question/25870256
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