Answer:
s(x) is t(x) ...
- horizontally compressed by a factor of 2,
- reflected across the y-axis, and
- translated downward 5 units.
Domain and Range
- t(x) has a domain of x ≤ 0, and a range of y ≥ 0.
- s(x) has a domain of x ≥ 0, and a range of y ≥ -5.
Step-by-step explanation:
t(x) is the square root function reflected across the y-axis and compressed horizontally by a factor of 2. That is, in f(x) = √x, the x has been replaced by -2x.
s(x) has the function t(x) <em>reflected back across the y-axis</em> and compressed horizontally by another factor of 2. It is also <em>translated downward by 5 units</em>, so that its origin (vertex) is at (0, -5).
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The graph shows you the domain and range of s(x). The domain is all numbers to the right of x=0, including x=0. That is ...
domain: x ≥ 0
The range is all numbers -5 or above:
range: y ≥ -5
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For t(x), the argument of the square root function must not be negative, which means the value of x cannot be positive.
domain: x ≤ 0
For non-negative values of radicand, the t(x) function will have non-negative values. So, the range is ...
range: y ≥ 0
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<em>Comment on solving problems like this</em>
Your graphing calculator can be your friend.
Diameter is from one side of the circle to the other through the middle
and the radius the from the middle to the edge of the circle
so radius is half the diameter
To solve this problem you must apply the proccedure shown below:
1. You have to find the distance from the center to the focus, as below:
c=√(a^2-b^2)
Where a is the major radius and b is the minor radius.
2. Therefore, by the graph, you have:
a=6
a^2=36
b=3
b^2=9
3. When you substitute the values, you obtain:
c=5.2
4. As you can see in the graph, the coordinates of the center is (3,4), then, the locations of the foci:
3+c=8.2
3-c=-2.2
The answer is: (-2.2,4) and (8.2,4)