Answer:
p percent of the observations are less than the value and (100 - p) percent are more than this value.
Step-by-step explanation:
Given : The pth percentile is a value such that approximately
Solution :
Definition : A percentile is a measure used in statistics indicating the value below which a given percentage of observations in a group of observations falls
So, The pth percentile means p percentage of observations in a group of observations falls bellow the value
So, (100-p) percentage of observations in a group of observations falls above the value
So, Option a is true
Hence p percent of the observations are less than the value and (100 - p) percent are more than this value.
4 1/3 there you go hope I helped
8, 17/12 9, 9/24 10, 13/10 11, 11/10
Answer:
Step 1: Distribute
to
and 
Step 2: Subtract from both sides of the equation 
Step 3: Add to both sides of the equation
Step 4: Divide both sides of the equation by 
Step-by-step explanation:
Step 1: Apply the Distributive Property. Then you must distribute
to
and 
Then:

Step 2: You must apply the Subtraction property of Equality and subtract
from both sides of the equation. Then:

Step 3: You must apply the Addition property of Equality and add
to both sides of the equation. Then:

Step 4: You must apply the Division property of Equality and divide both sides by
. Then:

Answer:
Amount invested at 7% = 16000
Amount invested at 9% = 12000
Step-by-step explanation:
Let x be the amount invested at 7% and y be the amount invested at 9%.
Since the total amount invested is $28000, therefore, we can set up the first equation as:

Secondly, we are give that sum of two investments is $2200. Therefore, we can write the second equation as:

Now we need to solve these two equations to get the values of x and y.
First of all, we multiply the second equation with 100 in order to get rid of decimal values.

Let us use substitution method here. First of all we will solve for y from first equation and plug that into second equation.


Therefore, amount invested at 7% is $16000 and amount invested at 9% is 28000-16000=$12000.