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8_murik_8 [283]
3 years ago
5

If f(x) is an odd function and the graph of f(x) includes points in Quadrant IV, which statement about the graph of f(x) must be

true?
It includes points in Quadrant I.
It includes points in Quadrant II.
It does not include points in Quadrant I.
It does not include points in Quadrant II.
Mathematics
2 answers:
lapo4ka [179]3 years ago
4 0
Answer is:
It includes points in quadrant II and it doesnt include points in quadrant I

Explanation:

For odd functions a rule is:
f(x) = -f(-x) or in other words
f(x) + f(-x) = 0

Because of this function can be in quadrants I and III or in quadrants II and IV as in pairs...
garri49 [273]3 years ago
3 0

Answer:

It includes points in Quadrant II.

It does not include points in Quadrant I.

Step-by-step explanation:

Given : If f(x) is an odd function and the graph of f(x) includes points in Quadrant IV.

To find :  which statement about the graph of f(x) must be true.

Solution : We have given that f(x) is an odd function is lies in Quadrant IV.

Definition of an odd function: the y-value of the function at negative x is always opposite sign as the y-value of function at opposite x.

Like  (x ,-y) or (x , -y)

In odd function x and y values are in opposite sign that mean odd function always lies in Quadrant II and  Quadrant IV.

It does not include points in Quadrant I

Therefore, It includes points in Quadrant II.

It does not include points in Quadrant I.

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