Do u have a pic of the problem?
H = 2sqrt2
D = 6sqrt3
In a 45,45,90 triangle the hypotenuse is (x)sqrt2 while the side lengths are equivalent being a single value x. Therefore, when given the hypotenuse and solving for the leg, divide 4 by sqrt2 to get 4sqrt2/2 which simplifies to 2sqrt2 when the denominator and numerator cancel.
In a 30,60,90 triangle the short leg x is across from the 30 degree angle meaning the angle across from the 60 degree angle is x times the sqrt of 3. Therefore the long leg is 6sqrt3
What do you mean... $245???
Answer:
2x^3 - 2x^2 - 12x
Step-by-step explanation:
2x(x - 3)(x + 2)
= 2x ( x^2 + 2x -3x - 6)
= 2x (x^2 - x - 6)
= 2x^3 - 2x^2 - 12x (answer).