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saveliy_v [14]
3 years ago
11

Whats the nth term of 13, 20, 27, 34...

Mathematics
1 answer:
tangare [24]3 years ago
5 0
I believe 20 i don’t rrly know
You might be interested in
the total cost of 4 pens at rs 20 each,5 pencils at Rs 5 each and 2 boxes at rs 60 each.make equation and solve (INTEGERS) plsss
Julli [10]

Answer:

225 rs

Step-by-step explanation:

cost of 1 pen = 20 rs

total cost of 4 pens = 20×4= 80 rs

cost of 1 pencil = 5 rs

total cost of 5 pencils = 5×5 = 25 rs

cost of 1 box = 60 rs

total cost of 2 boxes = 60×2 = 120 rs

Total= 80+25+120 = 225 rs

4 0
3 years ago
∠A = ___∘<br> Round your answer to the nearest hundredth.
larisa86 [58]

Answer: 45.58 degrees

Step-by-step explanation:

\sin A=5/7\\A=sin^{-1}(5/7) \approx 45.58^{\circ}

6 0
2 years ago
Read 2 more answers
Apply the distributive property to factor out the GCF.<br><br> 18d + 12= _________
stiv31 [10]

Answer:

6(3d+2)

Step-by-step explanation:

8 0
4 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Where is the solution located on a graph a system of equations?
geniusboy [140]
For a system of two variables and two equations, each equation will be a linear graph, and where the lines intersect is the solution as an ordered pair (x,y). If the lines don’t intersect (they’re parallel) so there is no unique solution.
5 0
3 years ago
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