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4 years ago

Help will give brainliest thank you

Mathematics

1 answer:

ddd [48]4 years ago

6 0

Plug in the numbers first (a = 2 and b = 3)
(2+5) - 3/3-4 + 2(3+3)/2

Remove parenthesis of 2 + 5
2+5 - 3/3-4 + 2 * (3+3)/2

Solve
2+5 - (-3) + 2 * (3 + 3)/2
2 + 5 - (-3) + 2 * 6/2
2+5 - (-3) + 12/2
2 + 5 - (-3) + 6
2 + 5 + 3 + 6
16 is your answer

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4 years ago

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A 51 foot piece of wire is cut into 3 sections so that the first section is three times as long as the second section and the se

kirill [66]

Answer:

The length of the longest section x = 36 ft

Step-by-step explanation:

Total length of the wire = 51 ft

Let first section of wire = x

Second section of wire = y

Third section of wire = z

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x = 3 y & y = 4 z

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3 years ago

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How am I supposed to figure this out if csc Theta(0) has a radical number on the top?

Harman [31]

$\bf csc(\theta)=\cfrac{hypotenuse}{opposite}\implies csc(\theta)=\cfrac{\sqrt{7}}{2}\cfrac{\leftarrow hypotenuse=c}{\leftarrow opposite=b}\\\\
-----------------------------\\\\
\textit{so hmm using the pythagorean theorem, we can say that}\\\\
c^2=a^2+b^2\implies \pm \sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
b=opposite\\
a=adjacent
\end{cases}\\\\
\textit{we'll assume is the + of the root, since you're not}\\
\textit{given further info on it, that means the I quadrant}\\\\
$

$\bf -----------------------------\\\\
cos(\theta)=\cfrac{a}{c}\qquad sec(\theta)=\cfrac{c}{a}\qquad tan(\theta)=\cfrac{b}{a}\qquad cot(\theta)\cfrac{a}{b}
$

so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant

keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant

but anyhow, use the I quadrant

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