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zimovet [89]
3 years ago
13

Please help! Picture is listed

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
Your answer Is D. Its important for them to be congruent Because if they werent then the whole shape would be thrown off. 
ss7ja [257]3 years ago
5 0
AD is parallel to BC
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The value of cosine is undefined at pi and 2pi radians.<br> TRUE<br> FALSE
Naddika [18.5K]

Answer: False

Step-by-step explanation:

False, the value of cosine at pi and 2pi is equal to -1 and 1 respectively. You can test this by using the pi circle or a calculator. Let pi = 180 degrees. Cosine is always defined and alternates between 1 and -1.

4 0
3 years ago
Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be
Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of t=0.6482

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

h(t)=-16t^2 +v_{o}t+s       Eqn(1).

Where:

h(t) : is the height range as a function of time

v_{o}   : is the initial velocity

s     : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

h(t)=-16t^2 + v_{o}t + 40        Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

h(t)=0-16t^2+60t+40=0

Using the quadratic expression to find the roots of the quadratic we have:

t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec

Since time can only be positive we reject the t_{2} solution and we keep that Ben's book took t=4.3276 seconds to reach the ground.

Similarly solving for Josh we obtain

t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

  • Josh's textbook reached the ground first
  • Josh's textbook reached the ground first by a difference of t=0.6482

3 0
3 years ago
Barrett works at an ice cream shop. The function f(x) represents the amount of money Barrett earns per gallon of ice cream, wher
Sliva [168]

The value of f(g(x)) is 6x^{3} +4

Explanation:

The function f(x) is given by

f(x)=2x^{2} +4

The function g(x) is given by

g(x)=\sqrt{3x^{3} }

To determine the value of f(g(x)), let us first substitute the value of g(x).

Thus, we get,

f(g(x))=f(\sqrt{3x^{3} } )

Now, substituting for x=\sqrt{3x^{3} } in the function f(x), we get,

f(g(x))=2(\sqrt{3x^{3} } )^2+4

Simplifying, the expression, we get,

f(g(x))=2({3x^{3} } )+4

Multiplying the term within the bracket, we have,

f(g(x))=6x^{3} +4

Thus, the value of f(g(x)) is 6x^{3} +4

Hence, the value of f(g(x)) represents the total amount of money that Barrett earns for working x hours.

4 0
3 years ago
Shara collected two different data sets and label them dataset S and data said T.
Kamila [148]

Answer:

What are you asking?

Step-by-step explanation:

4 0
3 years ago
What 89337 times 8<br><br> A-888998<br><br> B-903842<br><br> C-714696<br><br> D-847839
Romashka [77]

Answer:

C   714,696

Step-by-step explanation:

89,337 x 8 =

3 0
3 years ago
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