3 (k-12) = k-30
3k - 36 = k - 30
3k - k = -30 + 36
2k = 6
k = 3
Answer:
I don't see an O in the picture at all.
but here's how you solve it: just count the nodes between the species, the fewer the closer
I would go for E and I, only one step between them
Answer:
Sandy did not follow PEMDAS and added first instead of doing her multiplication and division and then her addition and subtraction the answer would be 18
Answer:
B
Step-by-step explanation:
The end behavior of a function is how the graph behaves as it approaches negative and positive infinity.
Let's take a look at each end.
As x approaches negative infinity:
As x approaches the left towards negative infinity, we can see that the graph is shooting straight upwards.
Therefore, as 
, our function f(x) is increasing and increasing up towards positive infinity.
Therefore, the end behavior at the left will be:
As x approaches (positive) infinity:
As x approaches the right towards positive infinity, we can see the that graph is also shooting straight upwards.
Therefore, the end behavior will be exactly the same. As x approaches positive infinity, f(x) <em>also</em> approaches positive infinity.
Therefore, the end behavior at the right will be:
Therefore, our answer is B.
Answer:
option c) x₁₁ + x₁₂ = 8000
Step-by-step explanation:
Given:
xij = gallons of component i used in gasoline j
gallons of component 1 available = 8,000
demand gasoline types 1 = 11,000
demand gasoline types 2 = 14,000
Here, we have only component 1 available i.e i = 1 only
( therefore, all the options containing i = 2 gets eliminated )
thus,
component 1 will fulfill the demand of gasoline types 1 and 2 i.e j = 1 and 2
hence,
the equation satisfying the above conditions comes out as:
x₁₁ + x₁₂ = 8000
that means gallons of component 1 used in gasoline 1 and 2 and the total equals to the gallons of component 1 available i.e 8000
