Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.
Answer:
see explanation
Step-by-step explanation:
The nth term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₅ is double a₇ , then
a₁ + 4d = 2(a₁ + 6d) , that is
a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )
4d = a₁ + 12d ( subtract 12d from both sides )
- 8d = a₁
The sum of n terms of an AP is
= 
[ 2a₁ + (n - 1)d ] , substitute values
= 
( 2(- 8d) + 16d)
= 8.5(- 16d + 16d)
= 8.5 × 0
= 0
Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
Answer: 35
Step-by-step explanation:
We substitute a for 1 and b for 6.
5(1+6)=5(7)=35
Answer:
Table C)
Step-by-step explanation:
