It’s a right angle! which equals to 90° you already have 20° and 8° so you add them together and you get 28. now you have to subtract 90-28 which equals to 62.
ANSWER: 62°
<h3>
Answer: Choice B</h3>
With matrix subtraction, you simply subtract the corresponding values.
I like to think of it as if you had 2 buses. Each bus is a rectangle array of seats. Each seat would be a box where there's a number inside. Each seat is also labeled in a way so you can find it very quickly (eg: "seat C1" for row C, 1st seat on the very left). The rule is that you can only subtract values that are in the same seat between the two buses.
So in this case, we subtract the first upper left corner values 14 and 15 to get 14-15 = -1. The only answer that has this is choice B. So we can stop here if needed.
If we kept going then the other values would be...
row1,column2: P-R = -33-16 = -49
row1,column3: P-R = 28-(-24) = 52
row2,column1: P-R = 42-25 = 17
row2,column2: P-R = 35-(-30) = 65
row2,column3: P-R = -19-36 = -55
The values in bold correspond to the proper values shown in choice B.
As you can probably guess by now, matrix addition and subtraction is only possible if the two matrices are the same size (same number of rows, same number of columns). The matrices don't have to be square.
You have the answer into the images.
Given cost function C(a) = 7.5a, where a is the number of T-shirts.
Let us complete table.
We need to plug a=1,2,3,4 in above function to get the costs to complete the table.
For a =1
C(1)= 7.5(1) = 7.50
For a =2
C(2)= 7.5(2) = 15.00
For a =3
C(3)= 7.5(3) = 22.50
For a = 4
C(4)= 7.5(1) = 30.00
In order to find the common difference we need to find the diffrences of costs 15-7.50 = 7.50
22.50-15.00=7.50.
<h3>Therefore, common difference is 7.5.</h3>
a represents the number of T-shirts.
Domain of a is the numbers we can take for a.
So, we can take value for a as 0 or greater value.
Therefore, domain for a would be a is gerater than or equal to 0.
<h3>Domain : a≥0</h3>
Answer:
a) 0.75
b)5.05
c)0.02
Step-by-step explanation:
a)
P(Y>5)=?
This part is solved in the given picture.
b)
The mean of a uniform distribution is (a+b)/2.
Where a=4.95 , b=5.15.
E(Y)=(4.95+5.15)/2
E(Y)=10.1/2
E(Y)=5.05.
c)
The variance of a uniform distribution is (b-a)²/2.
V(Y)=(5.15-4.95)²/2
V(Y)=0.2²/2
V(Y)=0.04/2
V(Y)=0.02.
