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krok68 [10]
2 years ago
7

How many kilograms is a rice packet that weighs 750 g? (Please answer quick!)

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

Answer:

0.750 kg

Step-by-step explanation:

Hi there ,

As you know 1 kg = 1000g

So when we convert g to kg then we divide the given value of grams by 1000.

So in this case we have 750 grams, changing it we have :

\frac{750}{1000}

Since there are 3 zeroes in 1000 we move the decimal point by 3 places to the left leaving the answer as : 0.750 kg or \frac{750}{1000} kg

Please mark me as brainliest if you found the above answer helpful

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Answer:

A (2, -8/5)

Step-by-step explanation:

The answer would be A I believe. This is because to get from C to D, it would be going down 6 and to the right by 10.

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and 10 * 3/5 = 6

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3 years ago
A self proclaimed psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the c
swat32

Answer:

The 95% confidence interval would be given (0.172;0.288).  

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the probability that the psychic correctly identifies the symbol on the card in a random trial

\hat p represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

n=200 is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the cases successful

\hat p=\frac{46}{200}=0.23 represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

Confidence interval

The confidence interval for a proportion is given by this formula:

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

0.23 - 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.172  

0.23 + 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.288  

And the 95% confidence interval would be given (0.172;0.288).

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

6 0
3 years ago
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