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maksim [4K]
3 years ago
6

Acceleration is sometimes expressed in multiples of g, where is the acceleration of an object due to the earth's gravity. In a c

ar crash, the car's forward velocity may go from to in How many g's are experienced, on average, by the driver?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0
<h2>Answer:</h2>

<em><u>Driver experiences 17.68 G's on an average.</u></em>

<h2>Step-by-step explanation:</h2>

In the question,

We know that in a car crash the speed of the car goes from the <u>speed of 26 m/s to 0 m/s</u> in <u>0.15 seconds</u>.

So,

The final speed, v = 0 m/s

Initial speed, u = 26 m/s

Also,

Time in seconds, t = 0.15 s

So,

Using the equation of law of the motion, we get,

v = u + at

0 = 26 + a(0.15)

a = -26/0.15

<u>a = -173.33 m/s²</u>

As, there is deceleration of the car is taking place the acceleration is in negative.

Now,

To convert it into the force in the <u>G's</u> we need to divide the <u>deceleration</u> by the <u>acceleration (gravity), g.</u>

So,

<u>G's experienced by the driver on an average</u> is given by,

\frac{173.33}{9.8}=17.68

<em><u>Therefore, on an average the driver experiences 17.68 G's.</u></em>

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