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aleksklad [387]
3 years ago
11

(PLEASE HELP ASAP!!). One's intelligence quotient, or IQ, varies directly as a person's mental age and inversely as that person'

s chronological age. A person with a mental age of 15 and a
chronological age of 30 has an IQ of 120: What is the chronological age of a person with a mental age of 20 and an IQ of 120?
The chronological age is
Mathematics
1 answer:
shusha [124]3 years ago
8 0

Answer:40

Step-by-step explanation:This is a variation question

From the statement. Let the mental age be M and the chronological  age be C, then

IQ ∝M ∝1/C

⇒ IQ ∝ M/C

Introducing the proportionality constant

IQ = KM/ C

Given : M = 15, C = 30 , 1Q = 20

Substitute the given values into the equation

i.e 120 = K x 15/ 30

    120 = k/2

therefore k = 240

substitute k = 240 into the equation, we have

IQ = 240M/C

To find C when IQ is 120 and M is 20, we will substitute into the generated formula

i.e 120 = 240 x 20 / c

     120c = 480

            C = 480/120

             C = 40

Therefore , the chronological age of a person with mental age of 20 and IQ of 120 is 40

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Which score indicates the highest relative position? I. A score of 2.6 on a test with X = 5.0 and s = 1.6 II. A score of 650 on
Zanzabum

Answer:

A score of 2.6 on a test with \bar X = 5.0 and s = 1.6 and A score of 48 on a test with \bar X = 57 and s = 6 indicate the highest relative position.

Step-by-step explanation:

We are given the following:

I. A score of 2.6 on a test with \bar X = 5.0 and s = 1.6

II. A score of 650 on a test with \bar X = 800 and s = 200

III. A score of 48 on a test with \bar X = 57 and s = 6

And we have to find that which score indicates the highest relative position.

For finding in which score indicates the highest relative position, we will find the z score for each of the score on a test because the higher the z score, it indicates the highest relative position.

<u>The z-score probability distribution is given by;</u>

              Z = \frac{X-\bar X}{s} ~ N(0,1)

where, \bar X = mean score

            s = standard deviation

            X = each score on a test

  • <u>The z-score of First condition is calculated as;</u>

Since we are given that a score of 2.6 on a test with \bar X = 5.0 and s = 1.6,

So,  z-score = \frac{2.6-5}{1.6} = -1.5  {where \bar X = 5.0 and s = 1.6 }

  • <u>The z-score of Second condition is calculated as;</u>

Since we are given that a score of 650 on a test with \bar X = 800 and s = 200,

So,  z-score = \frac{650-800}{200} = -0.75  {where \bar X = 800 and s = 200 }

  • <u>The z-score of Third condition is calculated as;</u>

Since we are given that a score of 48 on a test with \bar X = 57 and s = 6,

So,  z-score = \frac{48-57}{6} = -1.5  {where \bar X = 57 and s = 6 }

AS we can clearly see that the z score of First and third condition are equally likely higher as compared to Second condition so it can be stated that <u>A score of 2.6 on a test with </u>\bar X<u> = 5.0 and s = 1.6</u> and <u>A score of 48 on a test with </u>\bar X<u> = 57 and s = 6 </u> indicate the highest relative position.

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3 years ago
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