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garik1379 [7]
3 years ago
5

What are the amplitude, period, and phase shift of the given function? f(t)= -1/2 sin (3t-2π)

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

C

Step-by-step explanation:

For a sine/cos function given in the form f(x) = A sin (Bx+C) , we can say:

|A| is the amplitude

2π/B is the period, and

-C/B is the phase shift

For the function given f(t)=-\frac{1}{2}sin(3t-2\pi)

A = \frac{1}{2}

B = 3

C = -2π

Using the information given, we can find:

Amplitude is |-\frac{1}{2}|\\=\frac{1}{2}

Period is \frac{2\pi}{3}

Phase Shift is -\frac{-2\pi}{3}\\=\frac{2\pi}{3}

Hence, the correct answer choice is C

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Nonamiya [84]

Answer:

2160

Step-by-step explanation:

12×4×3×5÷2×6

Multiply 12 and 4 to get 48.

2

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Multiply 48 and 3 to get 144.

2

144×5

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Multiply 144 and 5 to get 720.

2

720

​

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Divide 720 by 2 to get 360.

360×6

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2160

6 0
2 years ago
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What percent of 150 is 63?
Ksju [112]
Well it can not divied so the answer is 234
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3 years ago
(HELP) What is the domain and range of this parabola?
Stels [109]

Answer:

D: [0,8]

R: [0,3]

Step-by-step explanation:

The domain is the x-values covered by the graph, while the range is the y-values. So to find each, find the lowest and highest x and y value; since this graph is continuous the domain and range will include all values between these points. In this case, the lowest x is 0 and the highest is 8; the lowest y is 0 and the highest is 3. Then to write the answer write is from least to greatest, finally, surround the point by a parenthesis or bracket. The difference is that parenthesis means the value is not included while a bracket means it is. On this graph all points are included, therefore brackets should be used.

3 0
3 years ago
PLEASE HELP! A positive number is 1/3 of another number. The sum of the numbers is five less than the square of the larger numbe
antoniya [11.8K]

Answer: The numbers are 1 and 3.

Step-by-step explanation:

Let x = smaller number , y= larger number.

As per given,

x=\dfrac{y}{3}   ...(i)

x+y=y^2-5       ...(ii)

Put value of x from (i) in (ii)

\dfrac{y}{3}+y=y^2-5\\\\\Rightarrow\ \dfrac43y=y^2-5\\\\\Rightarrow\ 3y^2-4y-15=0\\\\\Rightarrow\ 3y^2-9y+5y-15=0\\\\\Rightarrow\ 3y(y-3)+5(y-3)=0\\\\\Rightarrow\ (y-3)(3y+5)=0\\\\\Rightarrow\ y=3 \ \ or\ y=\dfrac{-5}{3}

Since numbers are positive , so y=3 is correct.

And x will be 1  [from (i)]

Hence, the numbers are 1 and 3.

7 0
2 years ago
If h(x) = │5x - 17│, find h(3).
arsen [322]

Answer:

2

Step-by-step explanation:

5x - 17

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However, there is an absolute value sign over the expression. Abs value makes negatives turn positive. So -2 becomes 2.

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