Ask question

Ask question

All categories

2 years ago

8

A store I selling all toaster ovens at 15% off. Write an equation in the form y=kx

1 answer:

slavikrds [6]2 years ago

5 0

The answer is y equals 0.85 x. Hope this help you

You might be interested in

Simplify -5(20 + 3).

sammy [17]

Whenever a number is beside a parenthesis without a sign it means multiplication. So you would use PEMDAS work in parenthesis then exponents, multiplication (from left to right) addition and subtraction (from left to right). so you would add 20+3 and get 23 then multiply that by -5 to get -115 as your answer.

4 0

3 years ago

Read 2 more answers

HELP PLEASE IM IN A TIMED TESTTTT !!!

mixas84 [53]

Answer:

Step-by-step explanation:

2. 9a +4c=43

a+c=7

The total tickets for adults and children = 7 (a+c =7) 7 people in all

price for adult = $9 (9a) Price per child =$4 (4c)

total price =$ 43

9a +7c = 43

3 0

3 years ago

In 2013, voyager 1 traveled 1,468,800 kilometers each day. Whats that in scientific notation

n200080 [17]

Answer: 1.4688 x 10^6

Step-by-step explanation: Number has to be in between 1 and 10. Moved the decimal 6 places so that is your exponent

8 0

3 years ago

The figure shows a right triangle RQT with

ki77a [65]

Answer:

QT 28 RQ 50 RT SP50 i belive

Step-by-step explanation:

4 0

3 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

<em>Find the length of DC</em>

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago