1800×6.5%×30=b
b-1800=a
a) $1,710
b) $3,510
I'm going to use the substitution method.
4x + 4y = -16
-8x - 6y = -20
4x + 4y = -16
- 4x - 4x
--------------------------
4y = -4x - 16
------ ------ ------
4 4 4
y = -x - 4
-8x - 6(-x - 4) = -20
-8x + 6x + 24 = -20
-2x + 24 = -20
- 24 - 24
----------------------------
-2x = 44
------- -------
2 2
x = 22
4(22) + 4y = -16
88 + 4y = -16
- 88 - 88
------------------------
4y = -104
------ ---------
4 4
y = -26
The answer is (22, -26).
Answer:
Step-by-step explanation:
First, distribute the 2 to the 3z and -6 within the parenthesis.
You know have 6z -12/5 + 6 = 10
Subtract 6 from both sides of the equation
6z -12/5 = 4
Multiply 5 on both sides of the equation
6z -12 = 20
Add 12 to both sides of the equation
6z = 32
Divide by 6 on both sides of the equation
z = 32/6
Simplify
z = 16/3
I hope that this helps! :)
Answer: 30 degrees
Step-by-step explanation:
All angles in a triangle add up to 180 degrees, so you can just write an equation to solve for the measure of angle F. Also, angle C is congruent to angle F because of CPCTC
124 + 26 + F = 180
150 + F = 180
F = 30
The measure of angle F is 30 degrees
Answer:
a) 8/10
b) 
c) Independent events
Step-by-step explanation:
The given information are;
The proportion of women than carries a mutation of the BRCA gene, P(A) = 1/600
The proportion of women in which the mutation develops breast cancer, P(B) = 8/10
a) The probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene is given as follows;
1 × P(B) = 1 × 8/10 = 8/10
b) The probability, P that a randomly selected woman woman will carry the mutation of the BRCA gene and will develop breast cancer is given as follows;
P(A) × P(B) = 1/600×8/10 = 1/750 = 
c) The events are dependent
Given that P(A) × P(B) = P(A∩B), the events of carrying the mutation and developing Breast cancer are independent events.