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yan [13]
3 years ago
11

Can someone pleaseeee answer these.its urgent

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

1) Rolling a 3 is unlikely and rolling a 4 is unlikely too.

2) The probability of niki drawing a green marble is likely and the probability of tom drawing a blue marble is unlikely.

Step-by-step explanation:

1) Since there is only one 3 out of 6 numbers, the probability of that outcome is 1/6, which is low. The same thing goes for throwing a 4.

2) The reason why it is equally likely for niki drawing a green is because there are more green marbles than the other marbles. You could see it as a fraction as well, which is 4/9 Which is very close to one half (4.5). For tom, there are less blue marbles which brings it down to the unlikely spot (fraction = 3/9)

Hopefully this helps, and hopefully it isn't too confusing.

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Find the degree of the monomial 23x^4
aev [14]

Answer:

The degree of the monomial is 4.

8 0
3 years ago
Find a formula for the described function. A rectangle has area 49 m2. Express the perimeter of the rectangle as a function of t
Anna71 [15]

Answer:

P(L)=2L+98m^2/L

Step-by-step explanation:

The area (A) of a rectangle is equal to the length (L) of one of its sides times its width (w)

A=L*w (eq. 1)

And its perimeter can be calculated with the next formula:

P=2(L+w) (eq. 2)

Solving for <em>w </em>in eq. 1, and plugging it into eq. 2

w=A/L (eq. 3)

P=2(L+A/L)=2L+2A/L (eq. 4)

We know that A=49m^2, plugging in this value into eq. 4, we finally get into the answer:

P=2L+98m^2/L

If the length of the rectangle is larger than its width:

L>w\\L>A/L\\L^2>\sqrt{A} \\|L|>\sqrt{A}

|L|>7

L7

We know that a length can't be negative value, so the only valid interval is L>7. The domine of P is then:

L>7

7 0
3 years ago
Helppp meeee pleaseeee
Alex_Xolod [135]

Answer:

y ≥ -2

Step-by-step explanation:

5y - 3 ≥ -13

   +3     +3

5y ≥ -10

5/5y ≥ -10/5

y ≥ -2

and since we didn't divide by any negative numbers the sign stays the same

6 0
3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
3 years ago
One of Shakespeare's sonnets has a verb in 11 of its 18 lines, an adjective in 13 lines, and both in 8 lines. How many lines hav
horrorfan [7]

Answer:

Step-by-step explanation:

The total number of lines, n(U) = 18

Let the number of lins with verb be n(V) = 11

Let the number of lines with adjectives be n(A) = 13

n(V n A) = 8

Find the number of lines that have a verb but no adjective, that is, n(V n A')

Mathematically, according to sets theory,

n(V) = n(V n A) + n(V n A')

So,

n(V n A') = n(V) - n(V n A) = 11 - 8 = 3.

Hence, only 3 lines have a verb but no adjectives.

4 0
3 years ago
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