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Anon25 [30]
3 years ago
11

What is the median of these figure skating ratings? 6.0 6.0 7.0 7.0 7.0 8.0 9.0

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

The median would be 7.0.

Step-by-step explanation:

The median of a set of numbers means it is the middle number. since this set has 7 numbers you would need to find the number that is in the middle of the set. This would be the 4th number since it is in the middle. 7.0 is your answer.

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Five plus three equals
8_murik_8 [283]

Answer: 8

Step-by-step explanation:

5

+

3

8

5 chicken nuggets + 3 more chicken nuggets equals 8

5 0
3 years ago
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What is the mean of the data set rounded to the nearest tenth 0.7 1.1 0.8 1.6 1.6 2.2 1.1
Rina8888 [55]
The mean (average) can be found by adding up all ur numbers, then dividing by how many numbers there are.

(0.7+1.1+0.8+1.6+1.6+2.2+1.1) / 7 = 9.1 / 7 = 1.3 <==


6 0
3 years ago
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Si el ∡P y el ∡Q son ángulos alternos internos, y la medida de un ángulo suplementario a uno de ellos mide 135° ,¿cuánto miden e
Hunter-Best [27]

Answer:

so sorry

Step-by-step explanation:

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7 0
3 years ago
Can someone please help me with these!!!!!
Alona [7]
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3 0
3 years ago
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
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