Answer:
15 seconds.
Step-by-step explanation:
∵ The distance covered by plane in first second = 100 ft,
Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,
So, distance covered in second second = 200,
In third second = 300,
In fourth second = 400,
............, so on....
Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds
( Sum of AP )
Suppose the distance covered in n seconds is 12,000 feet,
∵ n can not be negative,
Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.
Step-by-step explanation:
2x2 + 10 - 3x - 3 + 3
Solving like terms
2x2 - 3x + 10
Option B is the correct answer
Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580
