Other answers are<br> C) 75<br> D) 105

Find the area of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

Hunter-Best [27]

Answer: 25

Step-by-step explanation:

3 0

3 years ago

What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare

Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

$\text{Area of sector}=\frac{\theta}{360}\times \pi r^2$ , where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

$\text{Area of sector}=\frac{138}{360}\times \pi (3)^2$

$\text{Area of sector}=\frac{138}{360}\times 9\pi$

$\text{Area of sector}=10.83849$

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

$\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)$

$\text{Area of sector}=2(\frac{114}{360}\times 25\pi)$

$\text{Area of sector}=\frac{114}{360}\times 50\pi$

$\text{Area of sector}=49.74188$

Let us find difference of area as shown below:

$\text{Difference of areas}=49.74188-10.83849$

$\text{Difference of areas}=38.90339$

$\text{Difference of areas}\approx 38.9$

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0

3 years ago

Q19. Four positive whole numbers add up to 36

MAXImum [283]

Answer:

Step-by-step explanation:

let the numbers be 7x,y,y,y.

7x+3y=36

3y=36-7x

$y=\frac{36-7x}{3} \\let~x=3\\y=\frac{36-7 \times 3}{3} =\frac{15}{3} =5\\$

numbers are 7×3,5,5,5

or 21,5,5,5

21×5×5×5=2625

7 0

3 years ago

Fewer young people are driving. In year A, 67.9% of people under 20 years old who were eligible had a driver's license. Twenty y

aleksley [76]

Answer:

Case a Case b

margin of error 0.0216 0.0231

Interval estimate (0.7016 , 0.6795) (0.5031 , 0.4569)

margin of error is not same in both cases.

Step-by-step explanation:

a

At 95% confidence interval the interval estimate of number of 20 year old drivers in year A can be computed as

p' ± z $\sqrt{\frac{p'(1-p')}{n} }$

= 0.68 ± 1.96 $\sqrt{\frac{0.68(1-0.68)}{1800} }$

= 0.7016 , 0.6795

the margin of error can be written as

z $\sqrt{\frac{p'(1-p')}{n} }$

= 1.96 $\sqrt{\frac{0.68(1-0.68)}{1800} }$

= 0.0216

b

At 95% confidence interval the interval estimate of number of 20 year old drivers in year B can be computed as

p' ± z $\sqrt{\frac{p'(1-p')}{n} }$

= 0.48 ± 1.96 $\sqrt{\frac{0.48(1-0.48)}{1800} }$

= 0.5031 , 0.4569

the margin of error can be written as

z $\sqrt{\frac{p'(1-p')}{n} }$

= 1.96 $\sqrt{\frac{0.48(1-0.48)}{1800} }$

= 0.0231

c

Sample size is same in case A and B but proportion is different in both cases so margin of error is different in both cases

3 0

3 years ago

Logan’s town is building a volleyball court based on a scale drawing that is 20 centimeters by 40 centimeters and uses the scale

natita [175]

Answer:

1.62m^2

Step-by-step explanation:

From the problem statement, the scale of the drawing is

1cm:45cm (meaning that 1cm on the drawing represent 45cm in reality ofr actual)

first,let us convert 20cm to the actual drawing

20cm in actual will give 20*45=900cm

to meters =900/100= 0.9m

Secondly let us convert 40cm to the actual drawing

20cm in actual will give 40*45=1800cm

to meters =1800/1000= 1.8m

Now we can calculate the actual area in meters we have

area= 0.9*1.8

area= 1.62m^2

6 0

4 years ago

Other answers are C) 75 D) 105