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Fudgin [204]
3 years ago
12

PLZ HELP ME I WILL GIVE BRAINLIST!!! Why was the Internet originally constructed?

Computers and Technology
1 answer:
pochemuha3 years ago
5 0

Answer:

C. to provide online search capabilities

Explanation:

The first workable prototype of the Internet came in the late 1960s with the creation of ARPANET, or the Advanced Research Projects Agency Network. Originally funded by the U.S. Department of Defense, ARPANET used packet switching to allow multiple computers to communicate on a single network.

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What's the difference between kilobyte and kibibyte, and why was the IEC convention for computer international memories made???
Masja [62]

Answer:

The Kibibyte was developed to take place of the kilobytes in the computer science context where the Kilobyte stands for 1024 bytes. And the Kilobyte interpretation to mean 1024 bytes, conflicts the Standard definition of the prefix kilo or 1000. And the IEC convention for computer international memories was made to define the international standards for electrical, electronic and related technologies.

Explanation:

Please check the answer section.

8 0
4 years ago
Given the value x=false ,y=5 and z=1 what will be the value of F=(4%2)+2*Y +6/2 +(z&&x)?
Bezzdna [24]
<h2>Answer:</h2>

F = 13

<h2>Explanation:</h2>

Given:

x = false

y = 5

z = 1

F = (4%2)+2*Y +6/2 +(z&&x)

We solve this arithmetic using the order of precedence:

<em>i. Solve the brackets first</em>

=> (4 % 2)

This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then

4 % 2 = 0

=> (z && x)

This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.

In this case since the right operand is a false, the result will be 0. i.e

(z && x) = (1 && false) = 0

<em>ii. Solve either the multiplication or division next whichever one comes first.</em>

=> 2 * y

This means the product of 2 and y ( = 5). This will give;

2 * y = 2 * 5 = 10

=> 6 / 2

This means the quotient of 6 and 2. This will give;

6 / 2 = 3

<em>iii. Now solve the addition by first substituting the values calculated earlier back into F.</em>

F = (4%2)+2*Y +6/2 +(z&&x)

F = 0 + 10 + 3 + 0

F = 13

Therefore, the value of F is 13

5 0
3 years ago
What best describes the purpose of occupational safety and health Administration
IRISSAK [1]

Under the Occupational Safety and Health Act of 1970, employers are responsible for providing safe and healthful workplaces for their employees. OSHA's role is to help ensure these conditions for America's working men and women by setting and enforcing standards, and providing training, education and assistance.

5 0
3 years ago
Read 2 more answers
Carrie is looking at the Form Properties Sheet. Which tab will control how the data is displayed and the data source it is bound
Lemur [1.5K]
The Answer is: Data


Hope this help
8 0
3 years ago
1. Your task is to process a file containing the text of a book available as a file as follows:A function GetGoing(filename) tha
Irina18 [472]

Answer:

See explaination

Explanation:

#function to count number of characters, words in a given file and returns a list of words

def GetGoing(filename):

file = open(filename)

numbrOfCharacters =0

numberOfWords = 0

WordList = []

#iterate over file line by line

for line in file:

#split the line into words

words = line.strip().split()

#add counn of words to numberOfWords

numberOfWords = numberOfWords + len(words)

#find number of characters in each word and add it to numbrOfCharacters

numbrOfCharacters = numbrOfCharacters + sum(len(word) for word in words)

#append each word from a line to WordList

for word in words:

WordList.append(word)

#display the result

print("The number of characters: ", numbrOfCharacters)

print("The number of Words: ", numberOfWords)

#return the list of words

return WordList

#find matches for keywords given in textlist

def FindMatches(keywordlist, textlist):

for keyword in keywordlist:

keyword = keyword.lower()

print ("The number of occurrences of {} is: {}".format(keyword,len([i for i, s in enumerate(textlist) if s == keyword])))

#main

booktext = GetGoing("constitution.txt")

FindMatches (['War', 'Peace', 'Power'], booktext)

7 0
3 years ago
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