Question

Jerry deposited $10,000 in a bank account, and 10 years later he closes out the account, which is worth $18,000. The annual rate of interest that Jerry has earned over the 10 years is closest to:

Answer 1

Answer:

r=  6.054% per year

Explanation:

given that

principal P=  $10,000

final amount A= $18,000

time t= 10 years

To find the annual rate we will use the formula below and solve for r

$r = [(\frac{A}{P} )^\frac{1}{t} - 1]$

Substituting our data into the expression and solving for r we have

$r = [(\frac{18000}{10000} )^\frac{1}{10} - 1]\\\\r = [(1.8 )^\frac{1}{10} - 1]\\\\r = [(1.8 )^0^.^1 - 1]\\\\r = [(1.8 )^0^.^1 - 1]\\r={1.06054-1}\\\\r= 0.06054$  

Calculate rate of interest in percent

r = 0.06054* 100

r=  6.054% per year