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otez555 [7]
3 years ago
15

Question 2 of 4

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

The time it took for the bottle rocket to reach a height of 200 feet is 60 seconds.

Step-by-step explanation:

The function for the height of the bottle rocket (in feet), <em>t</em> seconds after  it is launched is:

h(t)=1157-16\ t

Compute the value of <em>t</em> as follows:

h(t)=1157-16\ t

200=1157-16t

 16t=1157-200\\16t=957\\

     t=59.8125\\t\approx60

Thus, the time it took for the bottle rocket to reach a height of 200 feet is 60 seconds.

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Answer:

-12x+20

Step-by-step explanation:

Subtract similar numbers:

2x - 14x = -12x

Product:

12 - 12x + 8

Group the terms that are similar:

-12x + 12 + 8

Add the numbers:

-12x + 20

Final answer:

-12x + 20

4 0
3 years ago
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weqwewe [10]

Answer:

v=-1.46 \ m/s

Step-by-step explanation:

So, as balloon reaches its maximum height i.e. 11 m , its velocity become 0.

Therefore, v_{top}=0 \ m/s.

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Now it is also given that upward direction is positive and downward direction is negative. So velocity should be negative.

Using equation of motion,

v_{final}^2 - v_{initial}^2 =2\times a\times displacement   .....eqn 1.

where , displacement = -11 m(because it displace towards down) and a=g=-9.8\ m/s^2

Putting these values in eqn 1 .

v_{final}^2-0^2 =2\times 9.8 \times 11

v = \pm1.46 m/s.

But as we know direction of velocity is downward.

Therefore, v=-1.46 \ m/s

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7 0
4 years ago
Tell whether the angles are complementary or supplementary. Then find the value of x.
gladu [14]

Answer:

  • 7) x = 5
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Step-by-step explanation:

Complementary angles form a right angle and supplementary angles form a straight angle.

<h3>#7</h3>

<u>Complementary:</u>

  • 65 + 5x = 90
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<h3>#8</h3>

<u>Supplementary:</u>

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3 years ago
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Answer:

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6 0
3 years ago
9x-2y=-21 2x+3y=16 Substitution
hjlf
9x-2y=-21 \\\\  9x=-21+2y \\\\ => \boxed{x=\frac{2y-21}{9}} \\\\ 2x+3y=16 \\\\ 2*\frac{2y-21}{9}+3y^{(9}=16^{(9} \\\\ 2(2y-21)+27y=144 \\\\ 4y-42+27y=144 \\\\ 31y=144+42 \\\\ 31y=186 \\\\ \boxed{y=\frac{186}{31}=6} \\\\ x=\frac{2*6-21}{9} \\\\ x=\frac{12-21}{9} \\\\ x=\frac{-9}{9} \\\\ \boxed{x=-1}
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