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coldgirl [10]
3 years ago
15

Help Pls. Due 10/4/18 Thank you❤️

Mathematics
2 answers:
vovikov84 [41]3 years ago
4 0
So I need help and this is not my stuff a school
mart [117]3 years ago
3 0

The change in elevation is -15 meters

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When using ANOVA, the sum of squares within is: Group of answer choices Showing the difference between the groups Effect varianc
prohojiy [21]

Answer:

When using ANOVA, the sum of squares within is:  Showing the difference between the Total SS and Between SS known as Error variance

Step-by-step explanation:

Within SS is also known as Error sum of squares . It is calculated by finding the difference between Total Sum of Squares and Between Sum of Squares

with the given degrees of freedom.

Within SS = Total SS - Between SS

Where

Total SS= ∑∑X²- C. F

Between SS= ∑T²j/r - C.F

Correction Factor = CF = Tj²/n

So the correct answer would be

Showing the difference between the Total SS and Between SS also known as   Error variance.

8 0
3 years ago
In class, 30 people have brown shoes, 5 have green shoes, and 1 has blue shoes.
Tresset [83]

Answer:

5 : 36

There are 36 people in total and only 5 have green shoes.

5 0
3 years ago
The sum of two numbers is 19. Their difference is 65. What are the numbers?
quester [9]
Isn't it 89 not 19 and if its that, its 12 and 77
6 0
3 years ago
What is 32767/32768 as a reduced fraction?
Anit [1.1K]
32,767/32,768 is in lowest terms and can't be reduced.
8 0
3 years ago
A portion of the graph of f(x) = −x2 − 2x + 8 is shown. Which of the following describes all solutions for f(x)?
Naily [24]

Answer:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3

Step-by-step explanation:

The given function is f(x)=-x^2-2x+8.

We want to select the option that describes all the solutions to the parabola.

The domain of the parabola is −5 ≤ x ≤ 3.

This means that  any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.

This can be rewritten as (a,-a^2-2a+8)

Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3.

7 0
3 years ago
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