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2 years ago

12

What number is three tenths less than 1?

2 answers:

miss Akunina [59]2 years ago

8 0

Answer:

7/10 or seven/tenths

liraira [26]2 years ago

7 0

7 tenths or seven tenths because if you count down in the tenths and one is a whole number 5...

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Help pls ............

Anestetic [448]

Well it sounds like a trick question but the answer is simple! If she runs 90 meters per minute, In one minute she will run 90 meters.

Answer 90

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2 years ago

Find the distance between the points (6, 5 square root 2) and (4, 3square root 2).

Sonbull [250]

The distance would be 2√3 , in other words it is 2 square root 3

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2 years ago

Read 2 more answers

Help with 10 please!

Alexus [3.1K]

Gabrielle is x years old.
Felicia is 6 years older.....so Felicia is x + 6
the mom is twice as old as felicia...so the mom is 2(x + 6)
the aunt is x years older then mom....so the aunt (tanya) is 2(x + 6) + x

so Tanya/s age is :
2(x + 6) + x =
2x + 12 + x =
13x + 12 <===

8 0

2 years ago

the simple interest paid on a loan over a period of two and a half years is birr 375. if the rate of interest was 8% per annum,

Reil [10]

Answer:

4678.5

Step-by-step explanation:

$\frac{375}{8} = 46.875\\$

46.875 * 100 = 4687.5

8 0

2 years ago

The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic

Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 10

r = number of success

p = probability of success which in our question is % of first-round

appeals that were successful, i.e.; 40%

So, here X ~ $Binom(n=10,p=0.40)$

(a) Probability that none of the appeals will be successful = P(X = 0)

P(X = 0) = $\binom{10}{0}0.40^{0}(1-0.40)^{10-0}$

= $1*0.6^{10}$ = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

P(X = 1) = $\binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= $10*0.4^{1} *0.6^{10-1}$ = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

P(X >= 2) = 1 - P(X = 0) - P(X = 1)

= 1 - $\binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful = P(X > 0.5)

For this probability we will convert our distribution into normal such that;

X ~ N( $\mu = n*p=4,\sigma^{2}= n*p*q = 2.4$ )

and standard normal z has distribution as;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

P(X > 0.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{0.5-4}{\sqrt{2.4} }$ ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0

2 years ago