Question

Given that events A and B are mutually exclusive, i.e., A?B = ? and P(A?B) =0, and that P(A)=0.7 and P(B)=0.2, find P(A or B).

Answer 1

Answer:

$P(A or B)= P(A \cup B) = 0.9$

Step-by-step explanation:

given ,      $P(A)=0.7$    $P(B)=0.2$

                   $P(A or B) = P(A \cup B) =0$

since it is mutually exclusive event ,  $P(A and B)= P(A \cap B) =P(A?B) = 0$

           $P(A \cup B) = P(A) + P(B) - P(A\cap B)$

            $P(A \cup B) = 0.7 + 0.2 - 0$

            $P(A \cup B) = 0.9$