39 squared = 39²
'Squared' means to put to the power of 2.
39*39 = 1521
Answer: 39² or 1521
Answer:
Area of the remaining triangle with the villager is 1243.13 m²
Step-by-step explanation:
Triangle ABC is the triangular plot of a villager shown in the figure attached.
Sarpanch requested the villager to donate land which is 6 m wide and along the side AC which measures 132.8m.
Other sides of the plot has been given as AB = 50m and BC = 123 m.
Now area of this land before donation = 
= 
= 3075 square meter
After donation of the land the triangle formed is ΔDBE.
In ΔABC,

tan(∠ABC) = 
= 0.4065
∠ABC = 
= 22.12°
In ΔEFC,
tanC = 
0.4065 = 
CF = 
CF = 14.76 m
Since DE = AC - (CF + AG)
= 132.8 - (2×14.76)
= 132.8 - 29.52
= 102.48 m
Now in ΔDBE,
sin(∠DEB) = 
sin(22.12) = 
DB = 102.48×0.3765
= 38.59 m
Similarly, cos(22.12) = 
0.9264 = 
BE = 102.48×0.9264
= 94.94m
Now area of ΔDBE = 
= 
= 1831.87 square meter
Area of remaining triangle with the villager = Area of ΔABC - Area of ΔDBE
= 3075 - 1831.87
= 1243.13 square meter
So we should reverse the equation to
10+10=2x
We know that 10+10 is 20
and 20 divided by 2 is 10
so x=10
We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
Answer:
x²+5x-49
Step-by-step explanation:
-7² -x+6x+x²
combine like terms
-x+6x is 5x
simplify -7² is -49
now rewrite the equation
x²+5x-49