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Varvara68 [4.7K]
3 years ago
12

PLEASE HELP AND SHOW WORK !!

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0
1. $21 divided by 6m= $3.5
2. Take the $3.5 and multiply by 11m =38.5m
3. $28 divide by $3.5=8m
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Eliminate the x and y
sp2606 [1]

Step-by-step explanation:

Eliminate the x:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by (-3)}\\\\\left\{\begin{array}{ccc}-3(x-2y)=(-3)(6)\\3x+y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-3x+6y=-18\\3x+y=4\end{array}\right}\\.\qquad\qquad7y=-14\\.\qquad\qquad y=-2

Eliminate the y:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by 2}\\\\\left\{\begin{array}{ccc}x-2y=6\\2(3x+y)=(2)(4)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=6\\6x+2y=8\end{array}\right}\\\\.\qquad7x=14\\.\qquad x=2

7 0
3 years ago
Identify all the hyperbolas which open horizontally
dimaraw [331]

Answer:

The hyperbolas which open horizontally are:

(x+2)^2/3^2-(2y-10)^2/8^2=1

(x-1)^2/6^2-(2y+6)^2/5^2=1

Step-by-step explanation:

A hyperbola with equation of the form:

(x-h)^2/a^2-(y-k)^2/b^2)=1 opens horizontally

Then, the hyperbolas which open horizontally are:

(x+2)^2/3^2-(2y-10)^2/8^2=1

(x-1)^2/6^2-(2y+6)^2/5^2=1


6 0
4 years ago
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8. You would use pi(d) to find the circumference of a circle when given the value of the circle's diameter.

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